0.01(x)^2=4

Solution for 0.01(x)^2=4 equation:

0.01(x)^2=4

We move all terms to the left:

0.01(x)^2-(4)=0

a = 0.01; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·0.01·(-4)
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.16}}{2*0.01}=\frac{0-\sqrt{0.16}}{0.02}
=-\frac{\sqrt{}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.16}}{2*0.01}=\frac{0+\sqrt{0.16}}{0.02}
=\frac{\sqrt{}}{0.02}
$